Problem :
( Link : Click
here to visit this HackerRank problem
page.
)
Given
five positive integers, find the minimum and maximum values that can be
calculated by summing exactly four of the five integers. Then print the
respective minimum and maximum values as a single line of two
space-separated long integers.
Input
Format
A
single line of five space-separated integers.
Constraints
- Each
integer is in the inclusive range
.
Output
Format
Print
two space-separated long integers denoting the respective minimum and
maximum values that can be calculated by summing exactly four of the
five integers. (The output can be greater than 32 bit integer.)
Sample
Input
1 2 3 4 5
Sample
Output
10 14
Explanation
Our
initial numbers are
,
,
,
,
and
.
We can calculate the following sums using four of the five
integers:
- If
we sum everything except
,
our sum is
. - If
we sum everything except
,
our sum is
. - If
we sum everything except
,
our sum is
. - If
we sum everything except
,
our sum is
. - If
we sum everything except
,
our sum is
.
As you can
see, the minimal sum is 
and the maximal sum is .
Thus, we print these minimal and maximal sums as two space-separated
integers on a new line.
**Hints:**
Beware of integer overflow! Use 64-bit Integer.——————————————————————————————————————————————–
Solution : (in C++ )
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <cstdint>
using namespace std;
int main()
{
int64_t arr[5];
int64_t temp, sum = 0;
for (int i = 0; i < 5; i++)
cin >> arr[i];
sort(arr, arr + 5);
for (int i = 0; i < 4; i++) {
sum += arr[i];
}
cout << sum << " “;
sum = 0;
for (int i = 1; i < 5; i++) {
sum += arr[i];
}
cout << sum;
return 0;
}